00:01
So we're going to prove this statement by induction.
00:03
The sum of 4n equals 2n times n plus 1.
00:06
First step is to solve a case for n equals 1.
00:09
So on the left -hand side, we'll just have 4 times 1, so 4.
00:13
On the right -hand side, we'll have 2 times 1 plus 1, so 2 times 2 will give us 4.
00:21
So we've solved the first case.
00:24
Now let's have a look at the case for n equals k.
00:27
So 2k times k plus 1 and the case for k plus 1 it's going to be 2 k plus 1 k plus 2.
00:43
Okay so i'm going to multiply both these out and try to find a way between them.
00:49
So this is going to be 2k squared plus 2k and this is going to be 2 times k plus 2 k plus 2.
01:02
2, it's going to be 2k squared plus 6k plus 4.
01:13
Now i'll make some space up here.
01:19
Now what i'm going to do to try to find a route between these is i'm going to split this polynomial up.
01:26
So i'm going to have 2k squared plus 4k plus 2 plus 2 plus 2 plus 2 plus 2...