00:01
We're asked to use mathematical induction to show that rectangular checkerboard with an even number of cells, one white and one black, by the statement.
00:20
We have that let pnk be the statement, a 2n by k.
00:40
So here we're assuming that there are an even number of rows.
00:45
And the thing is, he says an even number of cells, you have either the rows or the columns have to have an even number.
00:57
That loss of generality, we'll assume as any number of rows, and if not, they can just root get the checkerboards so that the columns become the rose.
01:06
Pnk is the statements, 2n times k checkerboard with one missing white and missing black square can be covered by dominoes and for the basis, say n equals 1, we're trying to prove p1k for all k in the positive integers.
02:00
So if you do this, like k, be a positive integer, consider a 2x4x4x4 with one missing white, one missing black square.
02:45
Let the two missing squares be the eighth and jth column for checkerboard.
03:17
If i is equal to j, then we just tally the checkerboard replacing dominoes vertically.
03:40
But if i is not equal to j, how the checkerboard replacing all dominoes vertically in the columns up to j minus 1 in the column.
03:55
From j plus 1 to n.
04:00
Sorry, there should be i minus 1 and the column from j plus 1 to n.
04:35
So up to i minus 1 and from j plus 1 to n, and then tile the remaining part by placing all dominoes horizontally, like bricks.
05:25
And so we have shown that statement p1 is true...