00:01
For this problem, we are asked to use newton's method to approximate a root for the given function with the specified value of x -not.
00:07
We have f of x equals x cubed minus 2 and x -not equals 1.
00:11
So the first thing that i'll note here is that we can easily find that f prime of x will be equal to 3x squared.
00:18
Now i'll walk through specifically one iteration and then just show the numerical results that we're looking for here.
00:24
So we start off with f of 1, which is going to be equal to 3 cube, or excuse me, 1 cubed, so 1 minus 2, giving us a value of negative 1.
00:35
And we have f prime of 1 will be equal to 3 times 1 squared or just 3.
00:41
So our x1 will be equal to 1 minus f of 1, negative 1, divided by f prime of 1, so divided by 3...