00:01
Okay, so to find x1, we're going to use the formula.
00:06
X1 is equal to x0 minus f of x0 over f prime of x0.
00:24
Okay, so here we're going to use our x0 value here, which is one.
00:30
So first you need to find f of x0.
00:33
So that means you just plug 1 into this into the function x cubed plus 3x squared plus 3x squared minus 1.
00:44
Okay, so this is going to equal.
00:48
So 1 cubed plus 3 times 1 squared minus 1.
00:55
So if we do this, we'll get 3.
00:59
Okay, and then next we're going to need to take the derivative.
01:02
So f prime of x is equal to.
01:09
So we take the derivative of this function.
01:13
So that'll be 3x squared plus 6x.
01:19
Okay, so then here we're just going to plug in x zero, or we're going to plug in 1.
01:24
So with that we get 3 times 1 squared plus 6 times 1.
01:30
And with that we get 9.
01:32
Okay, so then from here we're going to plug these two values, into this formula to get x1.
01:39
So x1 is going to be equal to x0, which is 1, minus f of x 0, which we calculated to be 3, and then f prime of x0, which is 9.
01:52
So if we do this, we will get 2 thirds.
01:56
Ok, so we can see that x1, which i'm going to put to the right hand side, is going to be 2 thirds.
02:03
Ok, so now we want to calculate x2...