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# Use Newton's method with the specified initial approximation $x_1$ to find $x_3$, the third approximation to the root of the given equation. (Give your answer to four decimal places.)$2x^3 - 3x^2 + 2 = 0$, $x_1 = -1$

## $$x_{3} \approx-0.6825$$

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given off of exes. Jack's Cubans tricks cripples to weaken. Differentiate of prime attacks is six X squared minus six bucks. So now we know that if axe is negative one then we know using the formula X The N plus one is excellent. My eyes off of xn over a promise x n We end up with negative 0.75 and then when x is negative 0.75 we have negative 0.68 25

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