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Problem 10 Easy Difficulty

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

$ \displaystyle h(u) = \int^u_0 \frac{\sqrt{t}}{t + 1} \,dt $

Answer

$h^{\prime}(u)=\frac{d}{d u} \int_{0}^{u} \frac{\sqrt{t}}{t+1} d t=\frac{\sqrt{u}}{u+1}$

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