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Problem 14 Easy Difficulty

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

$ \displaystyle h(x) = \int^{\sqrt{x}}_1 \frac{z^2}{z^4 + 1} \,dz $

Answer

$\frac{\sqrt{x}}{2\left(x^{2}+1\right)}$

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Video Transcript

given the original function, let's take the derivative which simplifies to exit the 1/2. We can also write this a squirt of backs over two times X squared, plus one.