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# Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. $\displaystyle h(x) = \int^{\sqrt{x}}_1 \frac{z^2}{z^4 + 1} \,dz$

## $\frac{\sqrt{x}}{2\left(x^{2}+1\right)}$

Integrals

Integration

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### Video Transcript

given the original function, let's take the derivative which simplifies to exit the 1/2. We can also write this a squirt of backs over two times X squared, plus one.

Integrals

Integration

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