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Problem 15 Easy Difficulty

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

$ \displaystyle y = \int^{3x + 2}_1 \frac{t}{1 + t^3} \,dt $

Answer

$3=\frac{3(3 x+2)}{1+(3 x+2)^{3}}$

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Video Transcript

Okay. We know we can use the chin rule. So we have three exposed to remember that per the fundamental fear of calculus, the teas now get substituted with excess and then the derivative of through exports to we know the cowfish in front of the exes. Three Therefore, we multiply this by three, which simplifies to be nine exports sex because it's three times three and then three times too. Don't forget, this multiplies by both thus and thus.