00:01
In this question we have to solve these three equations by augmented matrix method.
00:06
So if we form augmented matrix matrix, so we can form like that 1, 2, 1, x coefficient.
00:12
Here y population 3, minus 1, 1, there coefficient minus 6, 2, 2, and here constant times, 7, 0, minus 1.
00:22
So now i am applying operation in r3, that is, r3 minus r3 if i apply.
00:29
So what i'll get here? this minus this.
00:36
R3 minus r2.
00:38
So 1 minus 2 i'll get here minus 1.
00:41
This minus this i'll get here 2...