00:01
Hello everyone in this question you have to solve these given three equations by augmented matrix method so augmented matrix i can form as here x coefficients will come so 1 1 2 here y coefficients 1 minus 1 0 and here z coefficients minus 2 1 minus 1 and here constant terms minus 6 4 minus 1 now what i'll do i am applying operation 4 r2 writing r2 plus r3 so what i'll get here 1 1 minus 2 r1 will be same minus it and here r2 plus r3 if you write so this plus this 3 here this plus this minus 1 here i'll get 0 here i'll get 3 and this will be same 2 0 minus 1 minus 1 next next, next time i'm applying, this number applying is r1 plus r2.
01:08
So what i will get 3 plus 1 is 4, here it is 0, it is minus 2, and here it is minus 3.
01:18
The many comes with the same, 3, minus 1, 0, 3, and here 2, 0, minus 1, minus 1.
01:29
Next i'm applying, r3 i'm writing as 2r3.
01:36
2 r3 minus r1 so what i'll get here 2 r3 means 2 into 2 4 4 minus 4 0 here and here 2 into 0 minus 1 into 2 minus 2 minus 2 minus 2 that is 0 and here minus 1 into 2 minus 1 into 2 that is minus 2 and minus 3 that is 1 and minus 3 that is 1 so, the meanings will be same.
02:15
So 4 here, 0 minus 2, minus 3, here 3, minus 1, 0 3...