This is based on the laws of exponents which state that when you multiply numbers with the same base, you add the exponents.
So, we have:
$$\frac{\left(1 \times 10^{-3}\right)\left(3.28 \times 10^{6}\right)}{4 \times 10^{7}} = \frac{3.28 \times 10^{-3+6}}{4
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