00:01
Okay, so to start off, we're going to find the mold of sulfur.
00:04
So mold of s, which is going to be 0 .054 divided by 32, which is going to be 0 .0016875 moles.
00:24
And then we're going to corresponding, we find the molds of s02.
00:28
So since they're in a 1 -to -1 ratio, the molds of.
00:31
Of s -o -2 are also going to be 0 .001685.
00:39
Hence the enthalpy change is going to be negative 296 .84, which is the enthalpy change of formation for s -o -2, which we got from appendix l times 0 .0016875, which comes down to be negative 0 .5 kilojoules.
01:05
Next, we're going to take the value of formation of h .g .o, interpia formation of hco.
01:16
And this is decomposition.
01:18
It's the opposite of formation.
01:19
So we're going to just flip the sign...