00:01
Okay, so for this question, they're saying that we have sncl4 reacts with excess h2o to form sno2 and hcl.
00:11
So the first thing that we should do is we should write down the chemical equation.
00:17
Sncl4 liquid plus h2o liquid yields sno2 solid plus hcl.
00:30
So now we got to balance.
00:31
We got to make sure the equation is.
00:33
Balance so let's see we have one s n on both sides so s n is balanced right so one s n on both sides now let's look at cl 4 we have 4 c l 4 no we have 4 c ls on the left side right from here and we only have one on the right side so if we put 4 here we will balance out the cl now let's look at oxygen we have two oxygens on the right side, and we only have one on the left side, so we must balance it out.
01:10
If we add a two here, we would have two oxygens on both sides, and now looks like hydrogen.
01:15
So we look at hydrogen on the left, and we look at hydrogen on the right, and we see that there is four on both sides.
01:21
So now the equation is balanced.
01:22
So they want us to calculate the delta h when one gram of sncl4 is reacted...