00:01
Okay, so we'll notice that we have a difference inside of our summation.
00:05
So let's break this up into two summations.
00:10
So we have i squared minus the summation from i is equal 3 to n of our constant 3.
00:17
Okay, so looking at this, or looking at theorem 2 .1, we see that this is equation 3, and this here is equation 1.
00:26
So we can rewrite this as our last term.
00:29
Well, we see that our last term is just n.
00:32
So we have n times n plus 1 times 2n plus 1.
00:40
And then this is all over.
00:46
Actually, our starting term is 3.
00:49
And for our summation formulas, we need to start at 1.
01:02
Okay, so since our starting index isn't 1, we need to shift what we have.
01:07
So let's see.
01:10
So we'll set k to be equal to our i value.
01:18
And we want it to start at 1.
01:20
So that's just i minus 2.
01:26
And that gives me 3 minus 2, which is equal to 1.
01:30
And what about our ending term? ok, and since we subtracted 2 from our starting term, we'll subtract 2 from our ending term as well.
01:44
So now we have the summation of well, ok, we're not to solve for i.
01:53
So we have i is equal to k plus 2...