00:01
Okay, so we want to use synthetic division to solve for q of x and r of x.
00:06
Well, let's note that if we're using synthetic division, we need this term here to be a 1.
00:11
So we have to multiply by a 1 half and divide by a 1 half.
00:16
So we get a 3x cubed plus a 1ā2 all over a x plus 1 over 2.
00:24
Okay, so we have that our x value is a negative 1ā2.
00:29
And then we have a 3 is 0 for x squared, and x.
00:33
And we have a one -half.
00:37
Okay, so let's start by bringing down our three.
00:43
Three times negative one -half is a negative three over two.
00:46
Bring that down...