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Hello there.
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They want us to use the table 2 .9 to solve the following problems.
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So the first problem is a graduated soda contains 18 millimeters of water.
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What is the new water level? after 35 .6 grams of silver metal with a density of 10 .5 is submerged in the water.
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So how we go about this? we see our setup.
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And we got our 18 millimeters of water.
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Our 3 .5 .6 grams of silver and the density, which is 10 .5.
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So how we're going to do this to solve for the new water level? well, we're going to times the gram to the density.
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So we can solve for our milliliters or volume.
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And so we do the setup 10 .5 times 35 .6, where we get 373 .6.
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And then we're going to add it to the 18 millimeters of water where we end up getting 391 .8 millimeters of water.
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That's the new level.
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The next one is a thermometer containing 8 .3 grams of mercury has broken.
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If mercury has a density of 13 .6, what volume spilled? it is weird how they worded.
01:31
I could say how much.
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What's the amount of the volume estimates? i don't know.
01:37
That's just how they wrote it.
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So anywho, we got our grams.
01:42
Don't ask me why i have them space like that.
01:44
That's just how i wrote it.
01:46
And 13 .6, that's our density.
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Now we're just going to solve for the volume.
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So how we're going to set up, like before, density times grams equals the milliliters.
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And we're times, so it times 13 .6 by 83.
02:03
And this, i mean by 8 .3 and our answer is 112 .88 milliliters...