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Welcome to numerid.
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In the current problem, we will find a couple of probabilities.
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To start with, we will have to find the probability of 0 less than equals to z less than equals to 1 .2 equals to how much.
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So, if i bring this over here and try to explain you what i am trying to say, this will be 0 and see this is 1 so 1 .2 will be somewhere over here so we have to find how much area is this so if you see that value beyond 0 is always 0 .5 and value beyond this 1 .2 can be found out from the staple so instead of writing this we can write this to be probability of z greater than equals to 0 minus probability of z greater than equals to 1 .2 and we have this value to be 0 .5 minus now 1 .2 if you see 1 .2 is over here which is 0 .11151 so 0 .1151 and if i subtract that that would give me 948 0 .3 .49.
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So this would be the answer to this problem.
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Next will be, next up we have another problem.
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So i will use up this space only to explain.
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So let me just drag a little bit up here so that i get this place for writing.
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Next problem is probability minus 0 .9 less than said less than 0 .0.
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What is minus 0 .9? of course this is 0 and this will be minus 1.
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So minus 0 .9 will be this point.
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I want to find what area is this minus 0 .9.
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So this would be nothing but the area this this this this this this this in between area we can also think of in terms of this how we did.
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So whatever is less than this area is the same as more than this area, correct? this is 0 .9 positive.
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So we can again write probability area less than 0, probability z less than equals to 0 minus probability z less than equals to minus 0 .9, which can be substituted by probability z greater than 0 .9.
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It's the same tail left right.
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0 .9 is this.
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So this value will be 0 .1841.
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That is 0 .5 minus 0 .1841 which would result in 0 .1 first 9 and then 5 and then 1 and then 3 .0 .359.
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This is the answer of part b.
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So let me quickly clean the screen.
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And clean this up as well this.
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Now moving to problem number c, part c, probability 0 .3 less, oops, it looks like 6 .3, 0 .3 less than equal to z less than equal to 1 .56 will be equals to.
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Now see, this is where zero lies.
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So, 0 .3 would be somewhere over here.
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This 1 .5, this is 1 .56 will be over here.
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How much area is there in between this two? so we can clearly write probability z greater than equals to 0 .3.
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That will be the whole area minus this smaller white area, this area.
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So minus probability z greater than equals to 1 .56.
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What is the probability of 0 .3? greater than this.
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0 .3821 minus.
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What is the probability of this? 1 .56.
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So 1 .5 is over here and 1 .56 would be this value.
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So 0 .0594.
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0 .0594.
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So the answer that would get will be 7 .4.
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2 to 0 .3227.
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So this is the answer of part c.
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Hope you are able to understand these...