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Use the Born-Haber cycle and data from Appendix IIB and Table 9.3 to calculate the lattice energy of CaO. (Hsub for calcium is 178 kJ>mol; IE1 and IE2 for calcium are 590 kJ>mol and 1145 kJ>mol, respectively; EA1 and EA2 for O are -141 kJ>mol and 744 kJ>mol, respectively.)

$-3398 \quad k J(\operatorname{mol})$

Chemistry 102

Chemistry 101

Chapter 9

Thermochemistry

Thermodynamics

Chemical reactions and Stoichiometry

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So this question wants us to use thie born haber cycle and ah, bunch of data in the appendix is well has given the problem to finally lattice energy for C. E. O s. And now calcium oxide is formed by calcium solid plus one half o to gas to form seo solid. So we'LL use this reaction to determine the born haber cycle. And so the first thing we can start with is see a solid to see a gas, and the data we need for that has given the problem. Delta H sub of CIA equals one seventy eight killer Jules per mall, and that's the Delta age of sublimation to go from solid to gas. So now that we have C A gas, we have to remove an electron to form see a plus plus an electron. And that's given as the ionization energy one, which is five ninety killer Jules Permal. Next, we need to take our CIA plus and remove another electron to get C A two plus. And that's given his ionization energy, too, which is one one for five killer Jules promote. So now our calcium is in its basic elemental form that is all the data we need. So now we can move on to our oxygen. And so, for our oxygen, we first have to go from one half o two gas to Oh, and that will be our delta h of the binding energy of O two and that is equal to four ninety four killer Jules Permal. Now we want to just add one electron to ah ro to form. Oh, minus that will be our electron affinity. One negative one forty one killer Jules Permal. And then we want to add another electron two for mo to minus which will be R E a too. And that is seven forty for killing joules per mall. And so now that we have all of this information, we can find the lattice energy. And so I go to a new page and write out the entire formula. So you want the Delta h of formation off Theo, and that equals the lattice energy plus Delta h sublimation of seeing a plus our ionization energy one and our ionization energy to those air both for cia. Then we add our one half times Delta age finding energy of our O two then we can add ar e a one and a two. And so we want to solve for you. So a plug and everything but you and so are Delta H formation is six. Thirty four point nine equals you plus our delta h sub of C A, which is one seventy eight are I want in two, five, ninety and eleven forty five one half of our four ninety four minus one. Forty one day one and seven forty, forty eight. And that gives us a lattice energy of negative. Three, three, nine, eight Killer Jules Permal. So that will be our final answer.

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