Substituting $y=k$ into the given differential equation, we get:
\[2 \frac{d k}{d x}=5 k+40\]
Since $k$ is a constant, $\frac{dk}{dx}=0$. So, we have:
\[0=5k+40\]
Solving this equation for $k$, we get:
\[k=-8\]
So, $y=k=-8$ is a constant solution to the given
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