This gives us:
$$
\Delta H^{\circ} = [\Delta H_f^{\circ}(\mathrm{NH}_{3}(g)) + \Delta H_f^{\circ}(\mathrm{HCl}(g))] - \Delta H_f^{\circ}(\mathrm{NH}_{4} \mathrm{Cl}(s))
$$
From the given data, we find that $\Delta H^{\circ} = 1769 \, \mathrm{kJ}$. Since this is
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