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Use the data in Appendix 3 to calculate the equilibrium constant for the reaction $\operatorname{AgI}(s) \rightleftharpoons \mathrm{Ag}^{+}(a q)+$ $\mathrm{I}^{-}(a q)$ at $25^{\circ} \mathrm{C} .$ Compare your result with the $K_{\mathrm{sp}}$ value in Table $16.2 .$

$$8. 3 \times 10^{-17}$$

Chemistry 102

Chapter 17

Entropy, Free Energy, and Equilibrium

Thermodynamics

Rice University

University of Toronto

Lectures

00:42

In thermodynamics, the zeroth law of thermodynamics states that if two systems are in thermal equilibrium with a third system, they are also in thermal equilibrium with each other.

01:47

A spontaneous process is one in which the total entropy of the universe increases. In a spontaneous process, the system will move from an ordered state to a disordered state, such as from ice to water, or from a solid to a gas. The concept of spontaneity was introduced by Rudolf Clausius in 1850.

02:50

Use the data in Table 17.1…

Using the $K_{\mathrm{sp}…

04:32

Use the data in Table 15.3…

Use the $K_{\text {sp }}$…

Uh huh. Answer for the question. Here we have a reaction. H g i in solid state toe. Edgy. Positive in a Persephone. All right place. I negative 18 in It was home. Okay, Delta gee, note is equal to Delta G, if not into 80 positive plus delta. She not, if not into 18. Minus delta ci. Yes, Not into a G I silver iodide. Somebody putting values we have here went into 77.1 plus one into one minus 51.67 minus one into minus 66.3. Can't joy poem Oil? Yeah, is equal to 91.73 Killer Joel Permal. Yeah. And to you, we have K is equal to e exponent. Gee note rt is it Will to e minus 91.73 multiplied 10. Rest of the power tree divided by RT is 8.314 multiplied 298 Physical to e exponents, 37.2 Care is equal to eight going three multiply 10 exponent minus 70

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