Let's first simplify the expression inside the absolute value:
$$\left|\frac{n-1}{2n} - \frac{1}{2}\right| = \left|\frac{2(n-1) - n}{4n}\right| = \left|\frac{n-2}{4n}\right| = \frac{n-2}{4n}$$
since $n > 0$.
Now, we want to find an $N$ such that for all $n >
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