Question
Use the determinant to find out for which values of the constant $\lambda$ the matrix $A-\lambda I_{n}$ fails to be invertible.$$\left[\begin{array}{ll}2 & 0 \\1 & 0\end{array}\right]$$
Step 1
The identity matrix $I_{n}$ in this case is a 2x2 matrix with ones on the diagonal and zeros elsewhere. So, $A-\lambda I_{n}$ is: $$\left[\begin{array}{ll} 2-\lambda & 0 \\ 1 & -\lambda \end{array}\right]$$ Show more…
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