00:01
For problem 17, we're given a figure.
00:03
We're also given that rq equals tq, which means segment rq is equal to segment tq.
00:10
So we can show that by using our tick marks.
00:14
Angle qsr, which is this angle here, is 9a plus 48 degrees.
00:25
And angle qst, which is this angle here, is 6a plus 50 degrees.
00:32
We can't assume that these angles are congruent, so we use different labels for them.
00:39
Whoops, i put 58.
00:41
There we go.
00:43
They want us to find the measure of angle qst, which is this angle here.
00:48
So that's good news.
00:49
All we need to do is figure out what a is, so we can plug that in to figure out the whole angle qst.
00:56
Just gotta plug it into the expression.
01:00
So we need to figure out what we can do, especially with this 9a plus 48.
01:07
We want these angles to be equal, but we have to prove it.
01:10
And when we're proving things, we definitely like to use theorems.
01:14
So the theorem we want to use for this problem is the converse of the angle bisector theorem.
01:20
The converse of the angle bisector theorem says that if a point is in the interior of the angle, so q is on the interior of the angle, the whole angle is rst that we're looking at.
01:34
So q is on the inside.
01:37
If it's equidistant from the sides of the angle.
01:40
So the sides are rs and st.
01:43
Q has to be the same length away from rs as it is from st, which in this case it is because from q to r is the same length as from q to t.
01:56
We know that because they gave it to us in the beginning.
01:59
So q is on the interior.
02:01
It's equidistant from the sides, so that means that it's on an angle bisector.
02:05
So that means that sq, segment sq, is an angle bisector.
02:10
Well, that is awesome news because we know an angle bisector cuts the angle into two equal parts, which means that angle qsr is congruent to angle qst.
02:28
So now we only do need the same amount of tick marks.
02:32
I'm just going to make a second one here...