00:04
We're looking at question 19, which is a proof.
00:07
And i'm going to set it up as a two -column proof, but you could also do a flow proof or paragraph proof or whatever style of proof that you've been using in class.
00:20
And we'll fill in our statements and reasons.
00:30
And with this one, we have the same diagram for several proofs.
00:33
So one of the things to keep in mind is diagrams are not always drawn to scale.
00:37
So if things don't look equal, but you're told they're equal, you know.
00:41
They're equals.
00:42
So keep that in mind.
00:44
So our statements for the beginning, and with proof, you can do a couple different ways for two column proofs.
00:50
One way is to do all the statements and then list all the reasons.
00:54
Another is to do statements and reasons together.
00:56
I do it both ways.
00:58
Today i'm going to do the statements first and then the reasons.
01:00
So we're going to start with our given, which is ps is equal to our q, and the measure of angle one equals the measure of angle four.
01:23
And we're trying to prove that the measure of angle three equals the measure of angle two.
01:29
So what we want to do is get the triangles congruent.
01:32
If we can get the triangles congruent, then we can use corresponding parts to get that prove statement that we want.
01:41
So some teachers would let you just use these and imply that they're congruent.
01:45
Some teachers like the formality of changing it over.
01:47
So i'm going to change it over in case you have a formal teacher.
01:51
You could skip this step or these steps actually if your teacher doesn't make you convert to congruence.
01:58
So for the first one, we know that pq is or p .s is congruent to rq because they were equal.
02:05
And then the same thing for step three, the angle one is going to be congruent to angle four because they were equal in the given.
02:17
And that gives us a side and an angle.
02:20
So we need one more either side or angle.
02:23
And since they share the side qs, we know that qs is congruent to qs by the reflexive property...