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Use the elimination method to solve each system. …

01:22

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 93 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104

Problem 15 Easy Difficulty

Use the elimination method to solve each system.
$$
\left\{\begin{array}{l}
{x+y=-5} \\
{-x+y=-1}
\end{array}\right.
$$

Answer

$y=-3$
$x=-2$

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Elementary and Intermediate Algebra

Chapter 4

Systems of Linear Equations and Inequalities

Section 3

Solving Systems of Equations by Elimination (Addition)

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Video Transcript

to solve this system by elimination noticed that we have opposite ex terms. We have one x and we have negative one x. So when we add these equations together, the ex terms will cancel X plus Negative one x zero. Why plus why is too why on negative five plus negative one is negative. Six. So now we have to y equals negative six. We can divide both sides of that by two, and we have y equals negative three. Now we're going to find the value of X. So I'm going to take my first equation and substitute the Y value in there. So we have X plus Negative three equals negative five. Now we can add three to both sides and we get X equals negative too. Now I want to check my solution by using equation to and substituting my X and Y values in there. So that would be the opposite of negative, too. Plus negative three equals negative one. Let's see if that worked. Opposite of negative two is +22 plus negative. Three is negative. One. Yes, that's true. That's a good check. So now we write our solution as an ordered pair X comma y negative to calm a negative three

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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