00:01
We are going to look if these factors, a and b, are going to be factors of this f of x equation.
00:10
So to do that, we're going to do synthetic division.
00:13
We'll go ahead and set up our problem.
00:18
Once we have that, we'll go ahead and take a look at our first term and see what we need to get rid of this x cubed.
00:27
So we're going to do an x squared, gives us x cubed plus 4x squared.
00:34
Subtract that.
00:36
So 2x minus 4x is going to give us a negative 2x squared minus 11x minus 12.
00:45
So now we'll go ahead and take a look.
00:47
So we need to get negative 2x squared.
00:50
So we already got 1x and we'll do negative 2x.
00:54
It gives us negative 2x squared minus 8x.
01:02
So again we subtract that cancels those out.
01:05
Negative 11x minus a negative 8 turns this into plus, which leaves us with negative 3 minus 12.
01:17
So lastly, we do negative 3...