00:02
We're given a loudness function, l of x, where l is the loudness in decibels and x is the intensity of the sound.
00:12
I not is the intensity of the least intense sound that a human can hear.
00:18
Furthermore, we're given that for a car, l of x of c is 70 decibels.
00:29
So that would have x of c is the car intensity.
00:35
And we're given also that we have a truck, we'll call his intensity x sub t, that is 10 times the car.
00:45
So it's 10 times x of z.
00:48
And what we want to find is the loudness of that truck.
00:53
Now, you could reason it out that if we're going to increase the x by a factor of 10, and this is log base 10, log base 10 of something increased by a factor of 10 is increasing that log by one.
01:11
So if the car is 70 decibels, then the truck must be 80, right? because 7 plus 1 is 8, and then when you multiply it by this 10, you get 80.
01:19
So you can reason that out with logic.
01:22
But let's go ahead and do the math for the fun of it.
01:27
So we have that l of the car's intensity is 70.
01:33
So we can start with that and say we know that 70 equals 10 times the log of x over i not.
01:45
This is x subcar, it's not 10, x of i sub zero.
01:53
And so that if we divide both sides by 10, we get 7 equals the log of x sub c over i not.
02:03
If we want to get, if we want to know what x of c is, we're going to have to exponentiate.
02:08
So remember if there's no log, a base written next to the word log, it's implied to be 10.
02:14
It's the common log.
02:16
So if we want to exponentiate this, we start with a base, come around and grab the other side as our exponent, and then come back around and grab the insides.
02:25
So the car's intensity is over i0 equals 10 to the seventh...