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# Use the following information to answer the next seven exercise. Four basketball teams took a random sample of players regarding how high each player can jump (in inches). The results are shown in Table 13.15.$$\begin{array}{|l|l|l|l|}\hline \text { Team } & {1} & {\text { Team } 2} & {\text { Team } 3} & {\text { Team } 4} & {\text { Team } 5} \\ \hline 36 & {32} & {48} & {38} & {41} \\ \hline 42 & {35} & {50} & {44} & {39} \\ \hline 51 & {38} & {39} & {46} & {40} \\ \hline\end{array}$$At the 5% significance level, is there a difference in the mean jump heights among the teams?

## Thus, P-value is 0.1614 which is greater than the level of significance $0.05,$ so null hypothesis will be accepted. The acceptance of null hypothesis indicates at 5$\%$ level of significance there is no difference in the mean jump heights among the 5 teams.

#### Topics

Distribution and One-Way ANOVA

### Discussion

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### Video Transcript

before this problem, we have to know that what P valuing would reject more offices and what people you would accept. Noise is so, Jack, it's not lanky value this lesser than your significant level. And we would accept a normal offices when the key value this So in our in exercise before also turned to eat one 31 we know that our devalue its roughly 120 1614 and the Alfa given in this problem is quite 05 Therefore, we can see that he is larger than our equals too often. So this move that we would accept the noise offices.

Clark University

#### Topics

Distribution and One-Way ANOVA