use-the-following-information-to-answer-the-next-two-exercises-the-table-of-data-obtained-from-wwwba

Question

Use the following information to answer the next two exercises. The table of data obtained from www.baseball-almanac.com shows hit information for four well known baseball players. Suppose that one hit from the table is randomly selected.
TABLE CANNOT COPY.

Find P(hit was made by Babe Ruth).
$$\begin{array}{l}{	ext { a. } \frac{1518}{2873}} \ {	ext { b. } \frac{2873}{12351}} \ {	ext { c. } \frac{583}{12351}} \ {	ext { d. } \frac{4189}{12351}}\end{array}$$

Dawn Getman · Accepted Answer

Hi. We&#x27;re looking at the question that I asked the find of probability. The hit was made by papers and we&#x27;re using the table 3.21 which is right above it. So to find the probability of something, we look for the number of favorable outcomes out of the total number of outcomes. So in this case, the favorable outcomes would be our hits made by Babe Ruth. And so in this case, when you find the Babe Ruth Rowe and followed all the way over to the right, there were 2873. It&#x27;s made by Babers, and the total number of possible outcomes will be the total number of hits which, as you can see in your table, is 5 12,351 And so since this multiple choice has our answers written as fractions, you just want to find the one that looks like that. That&#x27;s choice. Be so our final answer is Choice B. 2873 over 12,351. Thank you

Dawn Getman · Answer

Hi. We&#x27;ve got a question here asking the probability that a hit was made by Ty Cobb given that the hit was a homerun and we have a table of information right above to help us with that answer. Remember that the probability of any than A given B is equal to the probability of A and B over the probability of B. So in this case, we&#x27;re trying to find the probability of Ty Cobb and ah, home run over the probability of home runs. So to find our answer, we&#x27;re gonna find the Ty Cobb bro and find the home run column. And where they meet is this 114 and then the home run column itself, which would be our total for home runs for the bottom. We go to the bottom of that that 17 20. And if you look at her choices since this one doesn&#x27;t actually have it divided out, its choice B 1 14 over 17 20. Thank you.

Lucas Everson · Answer

Hello. Welcome to the video. And today we&#x27;re gonna be talking about probability, particularly how we can determine if two events are independent or not. In this problem, we&#x27;re given a big table of values regarding various hits made by professional baseball players. If I&#x27;m not mistaken, they list four players, uh, most importantly, hang care and being one of them. And we are asked to determine if probability that any randomly selected hit on this chart was hit by Hank Aaron. And the event that the A randomly selected A hit is a double are independent events. And to do this, we have to determine whether or not the probability off Hank Aaron hitting it is the same or different if the probability of Hank Aaron hitting it given the hit, is a double, Um, and if if this is true, then they are, in fact independent. But if this part right here, given that that it needs to be a double. If this changes the probability that Hank Aaron hit it, then these two events are not independent. So, going into our chart, there are 3771 total hits made by Hank Aaron out of all the hits added together, which is 12,350 won and this equals 30.5% and we have to determine whether or not that is equal, which we&#x27;ve already determined. It&#x27;s not onto the amount of doubles made by Hank Aaron, which is 624 divided by the total amount of doubles recorded, which is 15 77 and that equals 40.1%. And these air obviously not equal and therefore the fact that in this probability the fact that, um, the hit needed to be a double affected the probability of it being Hank Aaron. Because of that, these two events are therefore not independent. So our answer is No, they&#x27;re not. And this is theano. This is the reason given in option C. So there&#x27;s our final answer.

Trang Hoang · Answer

So, um, burgers question the first start to answer what is our DF the waiter in what is our d of denominator? So do you have no Warriner is, um K minus one k is a total a number of different group. In this case, we have five. So therefore our DF numerator is five minutes oneness four for our d of denominator, we have in total 20 values minus que, which is a total number of different group. So and minus K equals to 20 minus five different group equal suphan team. So thanks. We would fine. What is our s one? As to us three s for s five. So as one s two s three s words, five, they are the sun of each column. So s one mean it would be equals to 65.3 us too close to 66 as three equals 21075 point 84. As for equals Oh, sorry. So este is equals to 65.6. That&#x27;s why I was like, Why the numbers so big s floor is equals to 65.7 as five equals to 67.7. Okay, So now, in order for us to calculate the p value, we have to know our what is our f statistic? Iss. So to tackle it F statistic, um, we would talk, really the mean square off between and means square off within. So for calculating means square between it would follow following formula. So the total cell Oh, me. So the total son of S J Square over NJ NJ is the number off value, Procol over the total. It&#x27;s off us, jay, that some would be square and over and so to write, it s in terms of s one to s five. We would have as one square over in our case over four plus as two square over four plus dr dot to s five square over four blindness as one plus as two plus dot dot dot to s five that some would then square over the total value. The total elements in the data is 20. So we know that, um, the calculations you can do it yourself by plucky as one in this equation. And then the final answer would be 0.90 30. So to calculate, do this is not unless this is, um cell square value. And now we need Now we cook late Bean Square, So means square would be as us over, uh, K minus one. So in our case is DF numerator. It would be serial 0.90 3/4. Our final answer would be equal to zero point to to six. This is a mess between, so we know that I&#x27;m as between equals this value. Now we gonna find m s within. So m s within with B equals to us as within over de of denominator. In our case, this 15 So for s s with then equals to us as total minus s s between. So, for us as total has the following equation the total value um, you&#x27;re X square liners some off all of your ex and then squaring that some over. And so in our case, the S s total would be equals two 1.7055 So now to calculate s with and we take s total minus as a Z, um, that s total minus as as between. So our final answer in this case would be our case would be 1.4795 But so now when we know our value for, uh, sorry. I made a mistake here. So this is This is a mess, Not s. So our s s value iss a Neary. Right? This hour s value is 0.903 My bet, And this would give us the result, um, of esto, as that&#x27;s what then it was zero point. Hey, zero to 25 And after calculating as as But then we can now confidently calculate the f statistic f statistic. We&#x27;ll wait s s within and then calculate m s within. So Emma&#x27;s within would be as s over. The DF denominator is 15. You would have 0.80 to 5 over 15. This would be equals two zero point 05 Thief. To calculate the f statistic, it would be equal to MLS between over s within. So m s between equals two. Um, let&#x27;s just grow up. And this between equals zero boy to to six over, um, as within 0.535 It give us an approximate numbers off. Four. Wait, Teoh One or 2.4 point two to just Let&#x27;s just round it up. Okay? So now we have the F statistic. Um, we calculate the P value in which f, um, for 50 a mess for 15 larger than four point to to now wait can use any, like software or online calculator. This would give us the results of 0.17

Dawn Getman · Answer

high on this question. We&#x27;re looking to find the probability that a musician is male and had private instruction. So with probability, we&#x27;re finding the number of favorable outcomes over the number of possible outcomes. So in this case, are favorable outcomes. Would be our male musicians, some musician, Okay, who is male, And they had to have private instructions. So we&#x27;re gonna follow the road that says male over and look for the column that says private instruction. And then we&#x27;re going to see where those two meet and those to me at the number of 15 and then on the bottom, we use the total possible outcomes, which in this case, would be all musicians. So when you find the total of all musicians, which is the bottom right corner of the table, you get 130. And when you divide that on the calculator, you get 0.115 which, when you round become 0.12 Thank you

Dawn Getman · Answer

Oh, hi, we&#x27;re looking at the question. They asked about the probability that a musician is see milk. So we&#x27;re going to look at the probability the musician is female and to find the probability of something. It&#x27;s the number of favorable outcomes over all possible outcomes. So in this case, the favorable outcomes would be the female musicians. So we&#x27;re looking to find a number of female musicians, and on the bottom would be all outcomes, which would be all musicians. Uh huh. Go. Here we go, a musician&#x27;s. So find our answer. We&#x27;re looking for the female musicians, so if you look in the left far left, it has gender. And if you find the road, this is female and follow that all the way to the right. You&#x27;ll see there&#x27;s a total of 72 female musicians, and then for all musicians. We can go to the bottom of that same column or the find the total on the far left and follow that all the way to the right. Either way, you&#x27;ll see that there&#x27;s 100 and 30 musicians total, which gives us when me divide it, a probability of zero 0.554 for the probability that a musician

Problem

Use the following information to answer the next …

Problem 110 Medium Difficulty

Answer

b that is $\frac{2873}{12351}$

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b that is $\frac{2873}{12351}$

Introductory Statistics

Srikar K.

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Barbara Illowsky, Susan DeanIntroductory Statistics

Srikar K.

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