00:01
Okay, today we're looking at calculating bond energy from standard enthalpysa formation.
00:07
So here we're looking at nh3, and we have the enthalpyase of formation for nitrogen and hydrogen.
00:17
So first we want to make a balanced equation, so we know how many molds of each to use.
00:22
So we know n2 is how it normally exists, and h2 is how hydrogen normally exists.
00:27
And these are making nh3.
00:30
Now to balance this, we need two nitrogen on each side, and so.
00:34
Six hydrogens on each side.
00:36
So these are the mole ratios we'll be working with.
00:39
Now to find enthalpys of formation and bond energies, it's usually set up such that delta h equals bonds broken minus bonds formed.
00:58
So here we already know delta h is negative 46 .1 kilojoules per mole.
01:04
And we'll be making two of these molecules from this bounce reaction.
01:09
Then bonds broken, we're breaking one and two molecule, so 472 .7, and we're breaking three hydrogen molecules.
01:24
So that will be all the bonds broken, and we're forming six nh bonds.
01:31
And this is what we're solving for...