Use the formula $P=-(\partial U / \partial V)_{S, N}$ to show that the pressure of a photon gas is $1 / 3$ times the energy density $(U / V)$. Compute the pressure exerted by the radiation inside a kiln at $1500 \mathrm{K}$, and compare to the ordinary gas pressure exerted by the air. Then compute the pressure of the radiation at the center of the sun, where the temperature is 15 million $\mathrm{K}$. Compare to the gas pressure of the ionized hydrogen, whose density is approximately $10^{5} \mathrm{kg} / \mathrm{m}^{3}$