00:01
So for this problem, what we see is that the absolute value of x less than a implies that negative a is less than x, which is less than a.
00:14
So we add one on each side and then simplify.
00:19
So what we have here is f of x minus 1, the absolute value of that being less than 0 .2.
00:28
So that tells us that a negative 0 .2 is less than f of x, which is minus 1, which is less than 0 .2.
00:41
So then when we add 1 on both sides, we get that 0 .8 is less than f of x is less than 1 .2.
00:50
So with that in mind, the graph shows that if this is the case, now we must verify that 0 .7 is less than x, which is less than 1 .1.
01:07
But on the other hand, we have x and must have verify this equality.
01:12
So x minus 1, the absolute value of that is less than delta...