00:01
In order to find the sign of s plus t, knowing the sign of s and the sign of t, we first need to find the cosine of s and the cosine of t.
00:12
Since we know that sine or cosine squared of theta is equal to 1 minus sine squared of theta, we can find cosine squared of theta by doing 1 minus sine squared of theta.
00:31
Our sign squared.
00:34
So we're going to use s first.
00:38
So to find the cosine squared of s, we can do 1 minus the sign of s squared, which is 4 over 9.
00:49
So that tells us the cosine squared of s is 5 over 9, which tells us that cosine of s is the square root of 5 over 3.
01:08
We can use the same logic to the cosine of t.
01:13
So the cosine squared of t is equal to 1 minus the sine squared of t which is 1 minus negative 1 3rd squared and 1 3rd squared would be 1 over 9 so cosine squared of t is equal to 8 9th so that tells us that the cosine of t is equal to the square root of 8, which is 2 root 2 over 3.
02:05
Now when working with square roots, we can have the positive and the negative version.
02:11
So we need to check our quadrants.
02:14
Since s is in quadrant 2, and that is where sign is positive but cosine is negative, that tells us that the cosine of, s negative square root of 5 over 3 and the t is in quadrant 4 which is where cosine is positive so our cosine of t will be positive 2 or 2 over 3 right so now we can use those values to help us to find our sign of s plus t so the sign of s plus t is equal to the sign of s plus t is equal to the sign of s times the cosine of t, plus the cosine of s times the sign of t.
03:09
So we can replace the values we have to the right.
03:13
The sign of s is two thirds, and the cosine of t was two root two over three, plus the cosine of s, which is negative root five over three, times the sign of t, which is negative root five negative one -third.
03:38
So this gives us 4 root 2 over 3 plus, because a negative and a negative makes it positive.
03:51
Sorry, not over 3, over 9.
03:55
4 root 2 over 9 plus root 5 over 9...