00:01
Okay, so in this question we are given the parent function graphs and asked to draw the second derivative graphs.
00:07
Our hint is to go through the first derivative graph first, so we're gonna go ahead and do that.
00:13
So let's identify our critical values.
00:14
That is where the slope is equal to zero.
00:17
So we have one, two, three right there.
00:22
And on the second function we have this one right here.
00:27
So what does that mean? well these are places where the function is going to cross the x axis on our first derivative.
00:39
So from this point to this point the slope of the line is decreasing.
00:47
From here to here we have an increasing.
00:50
Here to here we have a decreasing.
00:52
And from here to here we have an increasing.
00:55
So that means on our first derivative graph we're gonna go from negative to positive to negative to positive.
01:02
And since this is an x to the fourth function, we can kind of estimate this is gonna look a little bit like an x to the third.
01:12
So let's go ahead and draw that.
01:14
So initially it's negative.
01:15
We end up right about here where that critical value is.
01:20
We inch into the positive a bit and then after that we return back down for that other critical point.
01:33
We dip once more, hit that other side, and then go up increasing.
01:42
So then we're gonna do the same thing here.
01:44
Our critical values right here and right here is gonna look a little bit like an x to the x squared function right there.
01:52
From this point to this point we are increasing.
01:55
From this point to this point we are decreasing.
01:59
And from this point to this point we are increasing again.
02:02
So we're gonna go ahead and have the parabola be right about there...