Question
Use the Intermediate Value Theorem to show that there exists a number $c$ in the given interval such that $f(c)=M$. Then find its value.$$f(x)=x^{2}-x+1 \text { on }[-1,4] ; M=7$$
Step 1
Since $f(x)$ is a polynomial function, it is continuous on the entire real line, including the interval $[-1,4]$. Show more…
Show all steps
Your feedback will help us improve your experience
Dwijendra Rao and 56 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the Intermediate Value Theorem to show that there exists a number $c$ in the given interval such that $f(c)=M .$ Then find its value. $$f(x)=x^{2}-x+1 \text { on }[-1,4] ; M=7$$
Functions, Limits, and the Derivative
The Algebra of Functions
Use the Intermediate Value Theorem to show that there exists a number $c$ in the given interval such that $f(c)=M$. Then find its value. $$f(x)=x^{2}-4 x+6 \text { on }[0,3] ; M=4$$
One-Sided Limits and Continuity
Use the Intermediate Value Theorem to show that there exists a number $c$ in the given interval such that $f(c)=M .$ Then find its value. $$f(x)=x^{2}-4 x+6 \text { on }[0,3] ; M=4$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD