Question
use the Intermediate Value Theorem to verify that $f(x)$ has a zero in the given interval. Then use the method of bisections to find an interval of length $1 / 32$ that contains the Zero.$$f(x)=\cos x-x,[0,1]$$
Step 1
Since both $\cos x$ and $x$ are continuous everywhere, their difference is also continuous everywhere. Therefore, $f(x)$ is continuous on $[0,1]$. Show more…
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