Question
Use the Laplace transform table to evaluate:$\sum_{n=0}^{2}(-1)^{n} \int_{n}^{n+1} t e^{-2 t} d t$
Step 1
According to the Laplace transform table, the Laplace transform of $t e^{-at}$ is $\frac{1}{(s+a)^2}$. So, the Laplace transform of $t e^{-2t}$ is $\frac{1}{(s+2)^2}$. Show more…
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