Question
Use the Laplace transform to solve the given initial-value problem.$$\frac{d y}{d t}-y=1, \quad y(0)=0$$
Step 1
Using the property that the Laplace transform of $\frac{dy}{dt}$ is $sY(s)-y(0)$ and the Laplace transform of $y$ is $Y(s)$, we get $$sY(s)-y(0)-Y(s)=\frac{1}{s}.$$ Substitute $y(0)=0$ into the equation, we get $$sY(s)-Y(s)=\frac{1}{s}.$$ Show more…
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