The Laplace transform of a function $f(t)$ is denoted by $L[f(t)]$ or $F(s)$, and the Laplace transform of an integral from $0$ to $t$ of a function $g(t)$ is given by $L[\int_{0}^{t} g(t) dt] = \frac{1}{s}F(s)$. Therefore, we have:
$$
L[f(t)] = L[t e^{t}] +
Show more…