00:01
Hi everyone, so today we are going to solve these given differential equation, the system of given differential equation, that is dx divided by dt is equal to negative x plus y, divide and the other is d by d by dt that is equal to 2x.
00:26
And you have been given the condition that x of 0 is equal to 0 and y of 0 is equal to positive 1.
00:45
Now what we have to do over here we have to use the laplace transform in order to solve this system of given differential equation.
00:59
Now how will we solve it? so solution for this question is very simple.
01:12
Now first of all, we have to take the laplace transform of both sides of the both equations.
01:21
So let's take it.
01:24
Now, what we are going to do over here, we are going to use the linearity of the laplace.
01:37
Transform and we would have x prime is equal to negative x plus y so this is the given equation right and now we are going to take the lap plus transform so over here we have this that is equal to negative l of x sorry square bracket plus l so this is the first equation.
02:21
Next we have the second equation that is y prime is equal to 2x.
02:28
So this will become taking the lap plus transform negative y or 0 is equal to 2 l x.
02:42
Fine.
02:44
And what are we going to do next we are going to take group coefficients.
02:48
So we'll take the group coefficients, we would get s plus 1, l of x, that is negative, ly is equal to 0...