use-the-laws-of-exponents-to-simplify-do-not-use-negative-exponents-in-any-answers-left643-4right4-3

Question

Use the laws of exponents to simplify. Do not use negative exponents in any answers.
$$
\left(64^{3 / 4}\right)^{4 / 3}
$$

Amy Jiang · Accepted Answer

Okay, so we see that we have a power of two experts. So let&#x27;s use our powerful so we can multiply. It is still so that&#x27;s six before you&#x27;re part of 3/4 times for over three. We see there are three or four cancels, so we just left with 64.

Ankit Gupta · Answer

According to the question, we have to simplify 64 president of our three upon core all the rest of power or upon three losing the law explaining. Now, of course, we are simply going to multiply the exponents. So this will become 64 western powers. Three a concourse multiplied by poor upon three. So three upon former look like they&#x27;re called upon three is nothing but sing equals one From here We&#x27;re getting 64 rested in part one. And we know that any numbers REpower one is that number itself. So here we get support now through the This is not the final solution because 64 can again building As for wrested power three. So this will be our final answer. Or we can afford to simplify these writing for as two square to restore power to for the rest of our three. So again, we&#x27;re simply going toe. We&#x27;re simply going toe multiply the exponents for this will become to protest to the power six. So this will be the final answer because we can simplify this further. Right? So to restrict our six is the final answer

Amy Jiang · Answer

Okay, so let&#x27;s start by using our product Well, because we want to combine the following terms into a single fraction to get excited. Part 3/4. That&#x27;s one over the gate. Let&#x27;s see, uh, let&#x27;s combine that into a single fraction. So I multiply this term by 3/3 and this one by 4/4. So that gives me, um, talk. Let&#x27;s three times a day, which is 9/12 was 4/12. Tonight gives me nine plus four, which is 13 open to all, so he gets X to the power of 13/12.

Shaza Hammoud · Answer

and the questions required to simplify on the what? The final solution that include the negative explained. So as you can see, there&#x27;s the concept Number 61 depart by a power which has a base s and another power database T on the horses to the ah, power off too. So first off, or I&#x27;ll distribute that export to be inside the brackets. So what? What what will be? The result is six will be to the power off, too, because this is multiplied by the exponents off. Ah ah, This constant expansion is one. So just to multiply by one, which is two now and now it&#x27;s multiplied by s to the power off. Four multiplied four month blood by two, which is eight and minus seven, multiplied by two, which is minus 14. Now, I don&#x27;t want this negative explained to exist in my ass, so I have to and changed this time by taking the reciprocal off. The A hasty there&#x27;s appropriate is one of our tea. So this is 64 off two is 36 esta por eight and risa broken off the base t It just went over tea. So, in other words, it was incinerated. Now it&#x27;s indeed denominator and export will change to be paused a 14. So this is define a solution. There&#x27;s a question. I can&#x27;t simplify it more because D is different than us. They are not the same base, so this is defiance solution.

Shaza Hammoud · Answer

and there&#x27;s a question it&#x27;s required to simplify for expression on defy, not such that include Dina Graphics Pond. So inside either is a fraction, which is four over X to the third power, and the hole is do the negative third power as well. So what first we can do is just to distribute the Inegative exploring outside to be inside so this can be done by the and so before it becomes too far off minds or three over eggs to the board off three multiplied by my 23 So if the explosions will be multiplied by each other here, you can see as it&#x27;s four. So it means that it&#x27;s portable off one. Now we can&#x27;t apply minor three by one on my mind&#x27;s a three by three. So this leave it as it is for the world off my three for now, and it&#x27;s the over X for three months with blood by my three, which is minus nine. Now you can see there are negative exports, and I want them to be positive. How to do that is just by taking the reciprocal off the fraction so it means that X to the port off. None will become Indy. Never better on dhe. Fourth quarter off country now would become indeed, you know, Annettor. And then the export would become positive. So So now this is equals toe extra for off, nine over for multiplied by itself three times, which is 64. So this is the final solution off this question.

Shaza Hammoud · Answer

and it&#x27;s a question it&#x27;s required to simplify the following expression. As you can see, the suppression has the following Ah ah, The debate is a fraction on the power is and and the export is negative. So first, to get rid off this negative export, I have to I think there&#x27;s a broker of this fraction So three now will become Indian M aerator on export four will become Didn&#x27;t matter since it waas and the numerator on DDE. This hall is a broker of this fraction will be to the power off paused for now. Now what&#x27;s remaining is to distribute this outside explained inside your brackets And this would be what blood by each explored inside are off this base It&#x27;s 3 to 4 off one and we have export off four So forward to vomit blood by one and we&#x27;re being multiplied as well by four. So it will, but not by all the exponents inside the brackets. Three to the power off 12 about multiplied by 41 It&#x27;s like before is four on this is over. Extra war four months well by four is 16. So now what&#x27;s remaining is to compute Ah, 3 to 4 or four is 81 on its over export of 16. So this is D. C.

Problem

Use the laws of exponents to simplify. Do not use…

Problem 87 Easy Difficulty

Use the laws of exponents to simplify. Do not use negative exponents in any answers.
$$
\left(64^{3 / 4}\right)^{4 / 3}
$$

Answer

$$64$$

Related Courses

Elementary and Intermediate Algebra

Related Topics

Discussion

Top Algebra Educators

Heather Z.

Kayleah T.

Caleb E.

Michael J.

Algebra Courses

Absolute Value - Example 1

Absolute Value - Example 2

Recommended Videos

Watch More Solved Questions in Chapter 10

Video Transcript

Marvin L. Bittinger, David J. Ellenbogen,Barbara L. Johnson

Elementary and Intermediate Algebra

Heather Z.

Kayleah T.

Caleb E.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

$$64$$

Elementary and Intermediate Algebra

Heather Z.

Kayleah T.

Caleb E.

Michael J.

Absolute Value - Example 1

Absolute Value - Example 2

Marvin L. Bittinger, David J. Ellenbogen,Barbara L. JohnsonElementary and Intermediate Algebra

Heather Z.

Kayleah T.

Caleb E.

Michael J.

Marvin L. Bittinger, David J. Ellenbogen,Barbara L. Johnson

Elementary and Intermediate Algebra