00:01
We are asked to evaluate this definite integral here.
00:07
So for integrals with polynomials, we will use this tool.
00:13
So x to the n power, integrate with respect to x, is equal to x to the n plus 1 power divided by n plus 1.
00:23
So we can apply that here.
00:25
So we have the integral from negative 1 to 0 of x minus x squared, and then integrate with respect to x.
00:34
So when we apply our general power rule, the term x will become x squared over 2, and minus x squared will become minus x cubed over 3.
00:56
And this will be evaluated at 0 and negative 1.
01:01
So we plug in here to evaluate, we have 0 squared over 2 minus 0 .0.
01:10
Cubed or three...