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Chapter 3, problem 52 says use the periodic table to determine each quantity.
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The first quantity is the number of 3s electrons and magnesium.
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So let's find magnesium on our periodic table.
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It has atomic number of 12, so it's located here.
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Magnesium is located in the s block and is located in period 3.
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So the number of 3s electrons it takes to get to magnesium would be 1, 2.
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So our answer for magnesium is 2.
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Question b says the number of 3d electrons to get to chromium.
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Let's do the same thing.
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Our d block is located right here on the periodic table.
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And chromium is located in the fourth period.
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Now the d block is slightly different in that if it's in the fourth period, it's actually 3d.
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In the fifth period, we have 4d and et cetera.
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So the number of 3d electrons would look at the number of electrons in the period 4 of the d block.
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So if we're looking for chromium, we notice that it's one, two, three, four electrons to get to chromium.
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However, because the 4s and the 3d energy level are very, very close in energy, electron are going to be pulled out of the 4s orbital and placed into the 3d orbital, as opposed to being into the 4s orbital.
01:27
So instead of having for an electron configuration of chromium 4s2, 2, 3, d4, we don't have that, but instead our electron configuration is 4 as 1, 3d5...