Question
Use the position function $s$ (in meters) to find the velocity at time $t=a$ seconds.$s(t)=-4.9 t^{2}+5$(a) $a=1 ;$ (b) $a=2$
Step 1
The derivative of a function is found by applying the power rule, which states that the derivative of $x^n$ is $n*x^{n-1}$. So, the derivative of $s(t)=-4.9t^2+5$ is $v(t)=-9.8t$. Show more…
Show all steps
Your feedback will help us improve your experience
Sanchit Jain and 81 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the position function $s$ (in meters) to find the velocity at time $t=a$ seconds. $s(t)=4 t-4.9 t^{2},$ (a) $a=0 ;$ (b) $a=1$
Differentiation
Tangent Lines and Velocity
Use the position function $f(t)$ meters to find the velocity at time $t=a$ seconds. $$f(t)=-16 t^{2}+5, \text { (a) } a=1 ; \text { (b) } a=2$$
Use the position function $s$ (in meters) to find the velocity at time $t=a$ seconds. $s(t)=4 / t,$ (a) $a=2$ (b) $a=4$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD