Inductive Step:
Assume that for some arbitrary natural number $k$, $k^2 - k + 2$ is divisible by 2.
We want to show that this implies that $(k+1)^2 - (k+1) + 2$ is also divisible by 2.
We have:
\begin{align*}
(k+1)^2 - (k+1) + 2 &= k^2 + 2k + 1 - k - 1 + 2
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