Question
Use the Ratio Test to determine whether each series converges absolutely or diverges.$$\sum_{n=2}^{\infty} \frac{3^{n+2}}{\ln n}$$
Step 1
The Ratio Test states that if the limit as n approaches infinity of the absolute value of the ratio of the (n+1)th term to the nth term of a series is less than 1, the series converges absolutely. If the limit is greater than 1, the series diverges. If the limit Show more…
Show all steps
Your feedback will help us improve your experience
Linh Vu and 69 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the Ratio Test to determine whether each series converges absolutely or diverges. $$\sum_{n=1}^{\infty}(-1)^{n} \frac{n^{2}(n+2) !}{n ! 3^{2 n}}$$
Infinite Sequences and Series
Absolute Convergence; The Ratio and Root Tests
Use the Ratio Test to determine whether each series converges absolutely or diverges. $$\sum_{n=1}^{\infty}(-1)^{n} \frac{n+2}{3^{n}}$$
Use the Ratio Test to determine whether each series converges absolutely or diverges. $$\sum_{n=1}^{\infty} \frac{2^{n}}{n !}$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD