π The Study-to-Win Winning Ticket number has been announced! Go to your Tickets dashboard to see if you won! πView Winning Ticket

Georgia Southern University

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71

Problem 52

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R}\left(x^{2}-y\right) d y d x ;-1 \leq x \leq 1,-x^{2} \leq y \leq x^{2}$$

Answer

$\frac{4}{5}$

You must be logged in to bookmark a video.

...and 1,000,000 more!

OR

## Discussion

## Video Transcript

Okay, here we have the double inner girl minus one toe, one minus x squared. The X squared of X squared minus. Why, T o P X. Starting with an anti derivative. With respect, sir. Why? Since it's going to be X squared? Why? Minus y squared Cover two Evaluated Trump X squared Tio X squared. Okay, so something nice happens here. This is this term is going to give me zero, because it's going to be OK, x to the fourth minus, thanks to the fourth. So she's here, so that's great. So I only have this first term, and this is going to be X squared times just X squared, minus minus, x squared the ex, which I mean, what is this? That should just be X squared. Times to x squared, too. Next to the fourth. Okay. Okay. So we need inside. Riveted to X to the fourth. Well, that's gonna be too x to the fifth. Evaluated for Maria's fall into one that's going to be two fifths times one minus minus one. Just to serve for but

## Recommended Questions

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R} e^{x / y^{2}} d x d y ; \quad 1 \leq y \leq 2,0 \leq x \leq y^{2}$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R} \frac{1}{x} d y d x ; \quad 1 \leq x \leq 2,0 \leq y \leq x-1$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R}\left(4-4 x^{2}\right) d y d x ; 0 \leq x \leq 1,0 \leq y \leq 2-2 x$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R} x^{2} y^{2} d x d y ; \quad R$ bounded by $y=x, y=2 x, x=1$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$

\iint_{R} e^{2 y / x} d y d x ; \quad R \text { bounded by } y=x^{2}, y=0, x=2

$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R} x^{3} y d y d x ; \quad R$ bounded by $y=x^{2}, y=2 x$$

Evaluate the double integral over the given region $R$.

$$\iint_{R} \frac{y}{x^{2} y^{2}+1} d A, \quad R: \quad 0 \leq x \leq 1, \quad 0 \leq y \leq 1$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R} e^{2 y / x} d y d x ; \quad R$ bounded by $y=x^{2}, y=0, x=2$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$

\iint_{R} \frac{1}{y} d y d x ; \quad R \text { bounded by } y=x, y=\frac{1}{x}, x=2

$$

Use the region $R$ with the indicated boundaries to evaluate each double integral.

$$\iint_{R}(2 x+6 y) d y d x ; \quad 2 \leq x \leq 4,2 \leq y \leq 3 x$$