Question
Use the result in Exercise $23(b)$ to find the curvature at the stated point.$$y=x^{3} / 3 ; x=0$$
Step 1
The first derivative of the function $y = \frac{x^3}{3}$ is given by: $$y' = x^2$$ The second derivative of the function is given by: $$y'' = 2x$$ Show more…
Show all steps
Your feedback will help us improve your experience
Tanishq Gupta and 64 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the result in Exercise $23(b)$ to find the curvature at the stated point. $$ y=e^{-x} ; x=1 $$
VECTOR-VALUED FUNCTIONS
Curvature
Use the result in Exercise $23($ a) to find the curvature at the stated point. $$ x=e^{3 t}, y=e^{-t} ; t=0 $$
Use the result in Exercise $23($ a) to find the curvature at the stated point. $$ x=t^{2}, y=t^{3} ; t=\frac{1}{2} $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD