Question

Use the results of Problem 15.5 to relate $\overline{Y^2}$ to $\overline{G^4}$ for all times $t$. Show that $\overline{G^i}$ can then be determined since it is known that, when $t \rightarrow \infty$, the velocity must be given by the equilibrium Maxwell distrihution, so that $\frac{1}{2} m \overline{v^2}=\frac{1}{2} k T$. Find thus the explicit value of $\overline{G^2}$. Hence find also an explicit expression for $\overline{Y^2}$ valid at all times.

   Use the results of Problem 15.5 to relate $\overline{Y^2}$ to $\overline{G^4}$ for all times $t$. Show that $\overline{G^i}$ can then be determined since it is known that, when $t \rightarrow \infty$, the velocity must be given by the equilibrium Maxwell distrihution, so that $\frac{1}{2} m \overline{v^2}=\frac{1}{2} k T$. Find thus the explicit value of $\overline{G^2}$. Hence find also an explicit expression for $\overline{Y^2}$ valid at all times.
 
Show more…
Fundamentals of Statistical and Thermal Physics
Fundamentals of Statistical and Thermal Physics
Rief F. 1st Edition
Chapter 15, Problem 8 ↓

Instant Answer

verified

Step 1

5. While I don't have the exact problem statement, based on the question, it appears that Problem 15.5 established a relationship between $\overline{Y^2}$ and $\overline{G^4}$. Let's assume that this relationship is: $\overline{Y^2} = A \cdot \overline{G^4}$ where  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Use the results of Problem 15.5 to relate $\overline{Y^2}$ to $\overline{G^4}$ for all times $t$. Show that $\overline{G^i}$ can then be determined since it is known that, when $t \rightarrow \infty$, the velocity must be given by the equilibrium Maxwell distrihution, so that $\frac{1}{2} m \overline{v^2}=\frac{1}{2} k T$. Find thus the explicit value of $\overline{G^2}$. Hence find also an explicit expression for $\overline{Y^2}$ valid at all times.
Close icon
Play audio
Feedback
Powered by NumerAI
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Maxwell-Boltzmann Distribution
The Maxwell-Boltzmann distribution is a fundamental result in statistical mechanics that describes the distribution of velocities (or energies) of particles in an ideal gas at thermal equilibrium. This distribution depends on the temperature and mass of the particles, and it provides the probability that a particle has a particular velocity. Its form is essential for determining average quantities, such as moments of the velocity distribution, which are directly related to the kinetic energy and other thermodynamic properties of the system.
Equipartition Theorem
The equipartition theorem states that energy is equally distributed among all quadratic degrees of freedom in a system at thermal equilibrium. For each degree of freedom, the average energy is (1/2)kT, where k is Boltzmann’s constant and T is the absolute temperature. This theorem allows one to relate the statistical moments of the velocity (or kinetic energy) distribution to the temperature of the system, providing a key tool in linking microscopic behavior to macroscopic observables.
Statistical Moments
Statistical moments, such as the second or fourth moments, characterize the shape and spread of a probability distribution. In the context of kinetic theory and stochastic processes, the second moment often corresponds to quantities like the variance or mean squared value of a variable, while the fourth moment provides information about the kurtosis or tails of the distribution. These moments are used to establish relationships between different averaged quantities and to derive explicit expressions for system dynamics.
Time Evolution to Equilibrium
The time evolution toward equilibrium describes how a system initially out of equilibrium relaxes to a steady state that is described by the Maxwell-Boltzmann distribution. This process involves the progressive adjustment of statistical moments until they reach values consistent with equilibrium conditions. Analyzing how these moments evolve in time, and using the known limiting behavior at long times, allows one to determine explicit expressions for the moments at any time, connecting transient dynamics to equilibrium properties.
Relating Moments Using Equilibrium Constraints
By using the equilibrium conditions given by the Maxwell-Boltzmann distribution and the equipartition theorem, one can relate various moments of the system, such as expressing one moment in terms of another. This approach leverages the known limiting behavior (for example, as time approaches infinity) to fix unknown quantities or constants in the system’s evolution equations and to derive explicit time-dependent expressions for quantities of interest.

*

Recommended Videos

-
axgraduate-student-with-a-ruler-is-assigned-t0-each-bottle-and-at-signal-they-measure-the-positions-of-their-respective-particles-we-then-construct-histogram-of-the-results-which-should-matc-25749

A graduate student with a ruler is assigned to each bottle, and at a signal, they measure the positions of their respective particles. We then construct a histogram of the results, which should match |Ψ|², and compute the average, which should agree with ⟨x⟩. (Of course, since we're only using a finite sample, we can't expect perfect agreement, but the more bottles we use, the closer we ought to come.) In short, the expectation value is the average of repeated measurements on an ensemble of identically prepared systems, not the average of repeated measurements on one and the same system. Now, as time goes on, ⟨x⟩ will change (because of the time dependence of Ψ) and we might be interested in knowing how fast it moves. Referring to Equations 1.25 and 1.28, we see that d⟨x⟩/dt = ∫ x ∂/∂t |Ψ|² dx = iħ/2m ∫ x ∂/∂x (Ψ* ∂Ψ/∂x - ∂Ψ*/∂x Ψ) dx. To keep things from getting too cluttered, I'll suppress the limits of integration.

Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever